Cthul Mar 2010 71 2 May 28, 2010 #2 alysha230893 said: 10x+5y=20 as form of y=mx+c Click to expand... If the equation is \(\displaystyle 10x+5y=20\) Then Divide both sides by 5. \(\displaystyle \frac{10x+5y}{5}=\frac{20}{5}\) Which equates to \(\displaystyle 2x+y=4\) Subtract \(\displaystyle 2x\) from both sides \(\displaystyle -2x+2x+y=-2x+4\) Which equates to \(\displaystyle y=-2x+4\) Reactions: alysha230893
alysha230893 said: 10x+5y=20 as form of y=mx+c Click to expand... If the equation is \(\displaystyle 10x+5y=20\) Then Divide both sides by 5. \(\displaystyle \frac{10x+5y}{5}=\frac{20}{5}\) Which equates to \(\displaystyle 2x+y=4\) Subtract \(\displaystyle 2x\) from both sides \(\displaystyle -2x+2x+y=-2x+4\) Which equates to \(\displaystyle y=-2x+4\)
B bjhopper Nov 2007 985 175 Trumbull Ct May 28, 2010 #3 alysha230893 said: 10x+5y=20 as form of y=mx+c Click to expand... Hi alysha, Rearrange the given equation to the desired form 10x +5y= 20 so 5y=-10x+20 and y=-2x +4 form you want This equation is a straight line on coordinate paper. It has a slope of -2 and a y intercept of 4. Does this answer your question? bjh Reactions: alysha230893
alysha230893 said: 10x+5y=20 as form of y=mx+c Click to expand... Hi alysha, Rearrange the given equation to the desired form 10x +5y= 20 so 5y=-10x+20 and y=-2x +4 form you want This equation is a straight line on coordinate paper. It has a slope of -2 and a y intercept of 4. Does this answer your question? bjh