y=mx+c

Mar 2010
71
2
10x+5y=20 as form of y=mx+c
If the equation is
\(\displaystyle 10x+5y=20\)
Then

Divide both sides by 5.
\(\displaystyle \frac{10x+5y}{5}=\frac{20}{5}\)

Which equates to
\(\displaystyle 2x+y=4\)


Subtract \(\displaystyle 2x\) from both sides
\(\displaystyle -2x+2x+y=-2x+4\)

Which equates to
\(\displaystyle y=-2x+4\)
 
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Nov 2007
985
175
Trumbull Ct
10x+5y=20 as form of y=mx+c
Hi alysha,
Rearrange the given equation to the desired form

10x +5y= 20 so 5y=-10x+20 and y=-2x +4 form you want This equation is a straight line on coordinate paper. It has a slope of -2 and a y intercept of 4. Does this answer your question?


bjh
 
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