# y=asin(bx+c)+d

#### ToXic01

One of the questions is
y=-4sin2(x+pi/2)

how do i get it into this form
y=asin(bx+c)+d

Thanks

#### galactus

MHF Hall of Honor
Is that $$\displaystyle -4sin(2(x+\frac{\pi}{2}))?.$$

Sometimes posters will not use ^ for power and write something like x2 for x^2. You do not mean $$\displaystyle -4sin^{2}(x+\frac{\pi}{2})?.$$

mr fantastic

#### ToXic01

i double checked the question it is correct

#### SpringFan25

$$\displaystyle -4sin(2(x+\frac{\pi}{2}))$$

If the question really says that it is already in the required form, just expand the brackets to get

$$\displaystyle -4sin(2x+\pi)$$