T ToXic01 Mar 2010 27 0 May 29, 2010 #1 One of the questions is y=-4sin2(x+pi/2) how do i get it into this form y=asin(bx+c)+d Thanks

galactus MHF Hall of Honor Jul 2006 3,002 1,124 Chaneysville, PA May 29, 2010 #2 Is that \(\displaystyle -4sin(2(x+\frac{\pi}{2}))?.\) Sometimes posters will not use ^ for power and write something like x2 for x^2. You do not mean \(\displaystyle -4sin^{2}(x+\frac{\pi}{2})?.\) Reactions: mr fantastic

Is that \(\displaystyle -4sin(2(x+\frac{\pi}{2}))?.\) Sometimes posters will not use ^ for power and write something like x2 for x^2. You do not mean \(\displaystyle -4sin^{2}(x+\frac{\pi}{2})?.\)

S SpringFan25 May 2010 1,034 272 May 29, 2010 #4 \(\displaystyle -4sin(2(x+\frac{\pi}{2}))\) If the question really says that it is already in the required form, just expand the brackets to get \(\displaystyle -4sin(2x+\pi)\)

\(\displaystyle -4sin(2(x+\frac{\pi}{2}))\) If the question really says that it is already in the required form, just expand the brackets to get \(\displaystyle -4sin(2x+\pi)\)