H HeadOnAPike Oct 2009 20 0 May 19, 2010 #1 I forgot the rule for checking to see if a polynomial has any whole numbers solutions? In my case, specifically this cubic equation: \(\displaystyle B^3 + 2B^2 + 2B + 4\)

I forgot the rule for checking to see if a polynomial has any whole numbers solutions? In my case, specifically this cubic equation: \(\displaystyle B^3 + 2B^2 + 2B + 4\)

alexmahone Oct 2008 1,116 431 May 19, 2010 #2 \(\displaystyle B^3+2B^2+2B+4=0\) \(\displaystyle B^2(B+2)+2(B+2)=0\) \(\displaystyle (B+2)(B^2+2)=0\) \(\displaystyle B=-2\) is the only solution.

\(\displaystyle B^3+2B^2+2B+4=0\) \(\displaystyle B^2(B+2)+2(B+2)=0\) \(\displaystyle (B+2)(B^2+2)=0\) \(\displaystyle B=-2\) is the only solution.

H HeadOnAPike Oct 2009 20 0 May 19, 2010 #3 Thanks, but that's not exactly what I was looking for. I remember being taught a trick that immediately tells you the range of possible whole numbers solutions, but doesn't give you the solution.

Thanks, but that's not exactly what I was looking for. I remember being taught a trick that immediately tells you the range of possible whole numbers solutions, but doesn't give you the solution.

roninpro Nov 2009 485 184 May 19, 2010 #4 You're probably referring to the Rational Roots Theorem. See Wikipedia: Rational root theorem - Wikipedia, the free encyclopedia

You're probably referring to the Rational Roots Theorem. See Wikipedia: Rational root theorem - Wikipedia, the free encyclopedia