Does anyone know what the Maclaurin series of 1/\sqrt{x+1} is?

TriKri Nov 2006 363 29 Sep 9, 2012 #1 Does anyone know what the Maclaurin series of \(\displaystyle 1/\sqrt{x+1}\) is?

Prove It MHF Helper Aug 2008 12,897 5,001 Sep 9, 2012 #2 TriKri said: Does anyone know what the Maclaurin series of \(\displaystyle 1/\sqrt{x+1}\) is? Click to expand... Use Newton's Generalised Binomial Series with \(\displaystyle \displaystyle \begin{align*} (1 + x)^{-\frac{1}{2}} \end{align*}\).

TriKri said: Does anyone know what the Maclaurin series of \(\displaystyle 1/\sqrt{x+1}\) is? Click to expand... Use Newton's Generalised Binomial Series with \(\displaystyle \displaystyle \begin{align*} (1 + x)^{-\frac{1}{2}} \end{align*}\).

TriKri Nov 2006 363 29 Sep 9, 2012 #4 I just found a way to generalize back and forth error compensation and correction Last edited: Sep 9, 2012