# Volume

#### leebatt

Consider the given curves to do the following. 8 y = x^3, y = 0 , x = 4 Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about y = 8.

Last edited:

#### skeeter

MHF Helper
Consider the given curves to do the following. 8 y = x^3, y = 0 , x = 4 Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about y = 8.
did you sketch a graph ?

$$\displaystyle V = 2\pi \int_0^8 (8-y)(4 - 2\sqrt{y}) \, dy$$

check the result by using washers ...

$$\displaystyle V = \pi \int_0^4 8^2 - \left(8 - \frac{x^3}{8}\right)^2 \, dx$$

• leebatt

#### leebatt

I keep getting (1152 * Pi)/7. I am confused about why you have 4 - 2y^(1/3) when using the method of cylindrical shells. For the washer method
it makes sense. The outer radius is 8 and the inner is 8 - x^3/8.

I tried checking it with Maple and it still spits out the answer the answer from above. Maple just integrates Pi*(8-x^3/8)^2 over the interval x = 0 to x = 4.