Venn Diagram Word Question

Jun 2010
16
0
Rite I will supply what I think is the correct answer and if someone could confirm if this is correct or not I would be extremely grateful. Got a handful of these to do so obv need to know if im on rite track:

students reported the following facts: (a) 37% played football (b) 12% played basketball and football (c) 48% played neither basketball nor football.

Deduce the % which played basketball.

I worked it out to be 12% + 15% = 27%
 

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MHF Hall of Honor
Mar 2010
2,340
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Chicago
Rite I will supply what I think is the correct answer and if someone could confirm if this is correct or not I would be extremely grateful. Got a handful of these to do so obv need to know if im on rite track:

students reported the following facts: (a) 37% played football (b) 12% played basketball and football (c) 48% played neither basketball nor football.

Deduce the % which played basketball.

I worked it out to be 12% + 15% = 27%
I get the same answer, via 52% - 25% = 27%.
 

Soroban

MHF Hall of Honor
May 2006
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6,341
Lexington, MA (USA)
[Hello, rooney!

I too agree with your answer . . .


Students reported the following facts:
. . (a) 37% played football
. . (b) 12% played basketball and football
. . (c) 48% played neither basketball nor football.

Deduce the % which played basketball.

I worked it out to be 12% + 15% = 27% . . . . Yes!

Since 48% played neither sport,
. . then 52% played either Football or Basketball (or both).

I used the formula: .\(\displaystyle P(F \cup B) \;=\;P(F) + P(B) - P(F \cap B)\)


Substitute the known values: .\(\displaystyle 52\% \;=\;37\% + P(B) - 12\% \)

Therefore: .\(\displaystyle P(B) \:=\:27\%\)