L lehder Aug 2009 62 0 May 11, 2010 #1 Hi, \(\displaystyle E_1={(-x+2y; 2y-3x; x+y} /(x;y) \in \mathbb{R}^3\) I showed that \(\displaystyle E_1\) is a vector space but i don't know how to determine it's dimension???

Hi, \(\displaystyle E_1={(-x+2y; 2y-3x; x+y} /(x;y) \in \mathbb{R}^3\) I showed that \(\displaystyle E_1\) is a vector space but i don't know how to determine it's dimension???

N nosolution680 May 2010 5 1 May 11, 2010 #2 I think the diminsion is 2 because there are 2 "elements" or variables.

D dwsmith MHF Hall of Honor Mar 2010 3,093 582 Florida May 11, 2010 #3 lehder said: Hi, \(\displaystyle E_1={(-x+2y; 2y-3x; x+y} /(x;y) \in \mathbb{R}^3\) I showed that \(\displaystyle E_1\) is a vector space but i don't know how to determine it's dimension??? Click to expand... You showed \(\displaystyle E_1\) is a vector space of \(\displaystyle \mathbb{R}^3\)? How did you show that? Last edited: May 11, 2010

lehder said: Hi, \(\displaystyle E_1={(-x+2y; 2y-3x; x+y} /(x;y) \in \mathbb{R}^3\) I showed that \(\displaystyle E_1\) is a vector space but i don't know how to determine it's dimension??? Click to expand... You showed \(\displaystyle E_1\) is a vector space of \(\displaystyle \mathbb{R}^3\)? How did you show that?