L Lukybear Jul 2009 132 1 May 22, 2010 #1 A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes. Last edited by a moderator: May 22, 2010

A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes.

e^(i*pi) MHF Hall of Honor Feb 2009 3,053 1,333 West Midlands, England May 22, 2010 #2 Lukybear said: A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes. Click to expand... What does A stand for in this equation?

Lukybear said: A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes. Click to expand... What does A stand for in this equation?

mr fantastic MHF Hall of Fame Dec 2007 16,948 6,768 Zeitgeist May 22, 2010 #3 Lukybear said: A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes. Click to expand... Start by noting that the capacity of the vessel is A (since V ---> A as t ---> +oo). Therefore V = A/4 when t = 5. Use this to solve for k. Now find (in terms of A) V when t = 10 etc. Reactions: Lukybear and HallsofIvy

Lukybear said: A vessel is being filled at a variable rate and the volume of liquid in the vessel at any time t is given by: V=A(1-e^-kt) b) If one quarter of the vessel is filled in 5 minutes, what fraction is filled in the next five minutes. Click to expand... Start by noting that the capacity of the vessel is A (since V ---> A as t ---> +oo). Therefore V = A/4 when t = 5. Use this to solve for k. Now find (in terms of A) V when t = 10 etc.