P Plato MHF Helper Aug 2006 22,474 8,643 Oct 25, 2012 #2 pnfuller said: View attachment 25397i dont even know where to begin with this? Click to expand... pnfuller said: View attachment 25397i dont even know where to begin with this? Click to expand... Actually that can't be done unless it says that \(\displaystyle f\) is differentiable. If we assume that is what the question means then what if \(\displaystyle \frac{d[-f(x-h)]}{dh}=~?\).
pnfuller said: View attachment 25397i dont even know where to begin with this? Click to expand... pnfuller said: View attachment 25397i dont even know where to begin with this? Click to expand... Actually that can't be done unless it says that \(\displaystyle f\) is differentiable. If we assume that is what the question means then what if \(\displaystyle \frac{d[-f(x-h)]}{dh}=~?\).
H HallsofIvy MHF Helper Apr 2005 20,249 7,909 Oct 25, 2012 #3 Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! pnfuller, since the problem says "use L'Hopitals rule", perhaps you could begin by doing that?
Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! pnfuller, since the problem says "use L'Hopitals rule", perhaps you could begin by doing that?
P Plato MHF Helper Aug 2006 22,474 8,643 Oct 25, 2012 #4 HallsofIvy said: Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! Click to expand... It does not show \(\displaystyle f'\) on this computer. It could be that the image is so dark. I wish we could ban posting questions as images. Last edited: Oct 25, 2012
HallsofIvy said: Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! Click to expand... It does not show \(\displaystyle f'\) on this computer. It could be that the image is so dark. I wish we could ban posting questions as images.
P pnfuller Aug 2012 107 0 north carolina Oct 25, 2012 #5 well how do you take the derivative of the numerator with all the different variables? HallsofIvy said: Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! pnfuller, since the problem says "use L'Hopitals rule", perhaps you could begin by doing that? Click to expand...
well how do you take the derivative of the numerator with all the different variables? HallsofIvy said: Since the problem says that f' (NOT f) is continuous, I think we can assume that f is differentiable! pnfuller, since the problem says "use L'Hopitals rule", perhaps you could begin by doing that? Click to expand...