I guess my question is when do we know which sampling w/out replacement to do?

I have typically seen if we take one out one by one, to use sampling without replace, order matters.

If not, then do sample without replacement, order irrelevant.

If the question is about content without replacement the order makes no difference. That is the case in this question.

If from a group of six men and eight women we randomly select a committee of five.

What is the probability of getting three men and two women: $\dfrac{\binom{8}{2}\binom{3}{6}}{\binom{5}{14}}$ No order.

From the whole of fourteen at random we pick s Pres, VP, Sec & Treasure.

There are ${\mathscr{P}^{14}_4}=\dfrac{14!}{(14-4)!}=24024$ permutations ways to do that.

How many ways for the there to be $(W,M,W,M)~?$

How many ways for the there to be (Ellen,Mark,Jane,Max)?

The probability of one is $\dfrac{1}{24024}$ and of the other is $\dfrac{\mathscr{P}^{8}_2\mathscr{P}^{6}_2}{\mathscr{P}^{14}_4}$. Which is which & WHY?