Trigonometric Functions

Dec 2009
9
0
Hi! I can't figure this out:

The point (pi/4,1) lies on the function in the form y= sin kx. Determine k.

So I did:

1= sin k (pi/4)

Is that right? If it is, how do I solve the equation?
 
Jan 2008
588
242
Hi! I can't figure this out:

The point (pi/4,1) lies on the function in the form y= sin kx. Determine k.

So I did:

1= sin k (pi/4)

Is that right? If it is, how do I solve the equation?
Next step is to take the inverse sine of both sides.
 
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Dec 2009
9
0
I actually thought of that soon after posting this :) Thank you though!