R runner940 Oct 2008 23 1 May 23, 2010 #1 I am having difficulty getting past the first step of solving this problem, can someone help me or check this for me? Thank you (Nod) Original Problem: sin(x)^2 - sin(x)^4 = cos(x)^2 - cos(x)^4

I am having difficulty getting past the first step of solving this problem, can someone help me or check this for me? Thank you (Nod) Original Problem: sin(x)^2 - sin(x)^4 = cos(x)^2 - cos(x)^4

Prove It MHF Helper Aug 2008 12,897 5,001 May 23, 2010 #2 runner940 said: I am having difficulty getting past the first step of solving this problem, can someone help me or check this for me? Thank you (Nod) Original Problem: sin(x)^2 - sin(x)^4 = cos(x)^2 - cos(x)^4 Click to expand... \(\displaystyle \sin^2{x} - \sin^4{x} = \sin^2{x}(1 - \sin^2{x})\) \(\displaystyle = \sin^2{x}\cos^2{x}\) \(\displaystyle = (1 - \cos^2{x})\cos^2{x}\) \(\displaystyle = \cos^2{x} - \cos^4{x}\).

runner940 said: I am having difficulty getting past the first step of solving this problem, can someone help me or check this for me? Thank you (Nod) Original Problem: sin(x)^2 - sin(x)^4 = cos(x)^2 - cos(x)^4 Click to expand... \(\displaystyle \sin^2{x} - \sin^4{x} = \sin^2{x}(1 - \sin^2{x})\) \(\displaystyle = \sin^2{x}\cos^2{x}\) \(\displaystyle = (1 - \cos^2{x})\cos^2{x}\) \(\displaystyle = \cos^2{x} - \cos^4{x}\).