C cherryperry May 2010 13 0 May 29, 2010 #1 Lot 21 is a trapezoid with the two bases perpendicular to the road. The scale drawing below uses 1/2 inch = 40 ft. A) 1/2 acre B) 2 acres C) 2 1/2 acres D) 3 acres So here's how I try to solve it: A = 1/2 x 4 (5 + 3 1/2) A = 1/2 x 20 x 8 1/2 A= 85 What am I doing wrong? What steps do I take?

Lot 21 is a trapezoid with the two bases perpendicular to the road. The scale drawing below uses 1/2 inch = 40 ft. A) 1/2 acre B) 2 acres C) 2 1/2 acres D) 3 acres So here's how I try to solve it: A = 1/2 x 4 (5 + 3 1/2) A = 1/2 x 20 x 8 1/2 A= 85 What am I doing wrong? What steps do I take?

galactus MHF Hall of Honor Jul 2006 3,002 1,124 Chaneysville, PA May 29, 2010 #2 Did you use your scale that 1/4 inch equals 40 feet?. b1: How many 1/2 inches are in 3.5 inches?. 7 7*40=280 b2: How many half inches are in 5 inches?. 10 10*40=400 Proceed in that fashion and you should be OK. It's like that other problem I stepped through involving scales. Find the square feet form this and then divide by 43,560 to find the acres. Reactions: cherryperry

Did you use your scale that 1/4 inch equals 40 feet?. b1: How many 1/2 inches are in 3.5 inches?. 7 7*40=280 b2: How many half inches are in 5 inches?. 10 10*40=400 Proceed in that fashion and you should be OK. It's like that other problem I stepped through involving scales. Find the square feet form this and then divide by 43,560 to find the acres.

galactus MHF Hall of Honor Jul 2006 3,002 1,124 Chaneysville, PA May 29, 2010 #3 In real-life, scales on blueprints are usually given as 1" = however many feet. If 1/2 inch is 40 feet, then 1 inch is 80 feet. So, 5 inches would be 400 feet. You could proceed this way.

In real-life, scales on blueprints are usually given as 1" = however many feet. If 1/2 inch is 40 feet, then 1 inch is 80 feet. So, 5 inches would be 400 feet. You could proceed this way.