# technique of completing the square to transform the quadratic equation

Hey guys, this is a nice forum Im glad there is one out there that can help people with them skills.

Use the technique of completing the square to transform the quadratic equation below into the form (x + c)2 = a.

4x2 + 16x + 12 = 0

I seem to be having a bit of trouble figuiring this out...can someone help?

#### Pim

firstly, you'll want to get rid of the 4

$$\displaystyle 4x^2+16x -12 = 0$$
$$\displaystyle x^2+4x-3 = 0$$

Then, ask yourself, if you work out the brackets of $$\displaystyle (x+c)^2$$, what makes sure you get +4x ? In this case that is $$\displaystyle c=2 \frac{4}{2}$$, because $$\displaystyle (x+2)^2 = x^2 + 4x + 4$$
So, what you have now is:
$$\displaystyle (x+2)^2 = x^2 + 4x + 4$$
$$\displaystyle (x+2)^2 - 4 = x^2 + 4x$$
$$\displaystyle (x+2)^2 -7 = x^2 + 4x - 3$$
Therefore, $$\displaystyle (x+2)^2 = 7$$ is equivalent to the first equation.

Does that make it clear?

firstly, you'll want to get rid of the 4

$$\displaystyle 4x^2+16x -12 = 0$$
$$\displaystyle x^2+4x-3 = 0$$

Then, ask yourself, if you work out the brackets of $$\displaystyle (x+c)^2$$, what makes sure you get +4x ? In this case that is $$\displaystyle c=2 \frac{4}{2}$$, because $$\displaystyle (x+2)^2 = x^2 + 4x + 4$$
So, what you have now is:
$$\displaystyle (x+2)^2 = x^2 + 4x + 4$$
$$\displaystyle (x+2)^2 - 4 = x^2 + 4x$$
$$\displaystyle (x+2)^2 -7 = x^2 + 4x - 3$$
Therefore, $$\displaystyle (x+2)^2 = 7$$ is equivalent to the first equation.

Does that make it clear?
Thanks. Well sorta but the answer doesn't fit the from whats above.

MHF Hall of Honor
Hello everyone

I'm sure Pim meant to say:

$$\displaystyle 4x^2+16x+12=0$$
$$\displaystyle \Rightarrow x^2+4x+3=0$$

$$\displaystyle \Rightarrow (x+2)^2-1=0$$

$$\displaystyle \Rightarrow (x+2)^2=1$$

Hello everyone

I'm sure Pim meant to say:
$$\displaystyle 4x^2+16x+12=0$$
$$\displaystyle \Rightarrow x^2+4x+3=0$$

$$\displaystyle \Rightarrow (x+2)^2-1=0$$

$$\displaystyle \Rightarrow (x+2)^2=1$$