# Stuck with an algebraic expression. quick fix but my mind is gone blank

h(81-h^2) =154

#### skeeter

MHF Helper
$h^3 - 81h + 154 = 0$

rational root theorem yields $h = 2$ as one solution, therefore ...

$(h-2)(h^2+2h-77) = 0$

Can you determine the other two solutions?

1 person

#### Hanache

You can solve it by using the quadratic equation.

MHF Helper

#### neilkirk

I got it. Feel a bit of a dope now, the question even said 'one of the values is an 'integer'. Thanks for tge fast reply lads!!

#### deesuwalka

$h(81-h^2)=154$

$81h-h^3=154$

$h^3-81h+154=0$

Now factor out it.

$(h-2)(h^2+2h-77)=0$