Stuck with an algebraic expression. quick fix but my mind is gone blank

skeeter

MHF Helper
Jun 2008
16,217
6,765
North Texas
$h^3 - 81h + 154 = 0$

rational root theorem yields $h = 2$ as one solution, therefore ...

$(h-2)(h^2+2h-77) = 0$

Can you determine the other two solutions?
 
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Dec 2016
13
0
US
You can solve it by using the quadratic equation.
 
Dec 2016
6
0
Ireland
I got it. Feel a bit of a dope now, the question even said 'one of the values is an 'integer'. Thanks for tge fast reply lads!!
 
Sep 2016
84
19
India
$h(81-h^2)=154$

$81h-h^3=154$

$h^3-81h+154=0 $

Now factor out it.

$(h-2)(h^2+2h-77)=0$