standard form

Nov 2009
18
0
I do not understand the process of standard form
could someone please tell me how to write:

64000 in standard form

and

64 x 10^(-7) in standard form

and a little explanation if possible because i cannot get my head around it

thanks
 
May 2010
23
2
I think standard form is just AX^2 + BX + C
so the standard form of 64000 is
0X^2 + 0X + 64000
 

CaptainBlack

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I do not understand the process of standard form
could someone please tell me how to write:

64000 in standard form

and

64 x 10^(-7) in standard form

and a little explanation if possible because i cannot get my head around it

thanks
Not having your text or lecture notes I have no way of knowing what "standard form" means here. The most likely case is it is a number written with one digit before the decimal point multiplied by a power of \(\displaystyle 10\).

So:

\(\displaystyle 64000=6400.0 \time 10=640.00 \times 10^2= 64.000 \times 10^3=6.4000 \times 10^4\)

The last term on the right would in this case be standard form (you may or may not want to lose the trialling zeros depending on if they are significant or not)

In the second case you want to move the decimal point one place to the left which increases the power of \(\displaystyle 10\) by \(\displaystyle 1\) to give \(\displaystyle 6.4 \times 10^{-6}\).


CB
 
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