Solving for Exponents as Variables

Sep 2012
838
90
Canada
I have the equation \(\displaystyle Value = 6(0.92)^n\)
I need to know what the cost will be when the Value is 1

So I did this

\(\displaystyle Value = 6(0.92)^n\)
\(\displaystyle 1 = 6(0.92)^n\)
\(\displaystyle 1/6 = 0.92^n\)

I'm stuck there. Any help is appreciated!
 

topsquark

Forum Staff
Jan 2006
11,602
3,457
Wellsville, NY
I have the equation \(\displaystyle Value = 6(0.92)^n\)
I need to know what the cost will be when the Value is 1

So I did this

\(\displaystyle Value = 6(0.92)^n\)
\(\displaystyle 1 = 6(0.92)^n\)
\(\displaystyle 1/6 = 0.92^n\)

I'm stuck there. Any help is appreciated!
Hint: \(\displaystyle \log_{10} \left ( 0.92 ^n \right ) \) is what?

(or you could use ln just as easily.)

-Dan
 
Sep 2012
838
90
Canada
Hint: \(\displaystyle \log_{10} \left ( 0.92 ^n \right ) \) is what?

(or you could use ln just as easily.)

-Dan

Lol, I'm sorry but I have no Idea what log and In are or how to solve that!