# Solving for Exponents as Variables

#### sakonpure6

I have the equation $$\displaystyle Value = 6(0.92)^n$$
I need to know what the cost will be when the Value is 1

So I did this

$$\displaystyle Value = 6(0.92)^n$$
$$\displaystyle 1 = 6(0.92)^n$$
$$\displaystyle 1/6 = 0.92^n$$

I'm stuck there. Any help is appreciated!

#### topsquark

Forum Staff
I have the equation $$\displaystyle Value = 6(0.92)^n$$
I need to know what the cost will be when the Value is 1

So I did this

$$\displaystyle Value = 6(0.92)^n$$
$$\displaystyle 1 = 6(0.92)^n$$
$$\displaystyle 1/6 = 0.92^n$$

I'm stuck there. Any help is appreciated!
Hint: $$\displaystyle \log_{10} \left ( 0.92 ^n \right )$$ is what?

(or you could use ln just as easily.)

-Dan

#### sakonpure6

Hint: $$\displaystyle \log_{10} \left ( 0.92 ^n \right )$$ is what?

(or you could use ln just as easily.)

-Dan

Lol, I'm sorry but I have no Idea what log and In are or how to solve that!