I'm going over my old textbooks in preparation for going back to university, and one question has me totally stumped.

I understand when encountering problems like \(\displaystyle $3^2^x-9(3^x)=0\) that you substitute for the exponential e.g. \(\displaystyle $y=3^x\) and solve from there, but i've now been presented with:

\(\displaystyle 2^2^x-2^x^+^1+1=0\)

Can anyone advise me how I go about solving this? I'll no doubt kick myself when I see it, but I just can't figure out what to do! (Headbang)