C cron1003 Apr 2010 5 0 May 10, 2010 #1 Please help me.. dy + 7x dx = 0 Given y(0)=3 Last edited: May 10, 2010

D dwsmith MHF Hall of Honor Mar 2010 3,093 582 Florida May 10, 2010 #2 cron1003 said: Please help me.. dy + 7x dx = 0 assume dy(0)=3 Click to expand... Separable equation. dy(0)=3 or y(0)=3? \(\displaystyle dy=-7xdx\rightarrow\int dy=-7\int xdx\rightarrow y=\frac{-7x^2}{2}+C_1\) If you mean y(0)=3, then C=3. \(\displaystyle y=\frac{-7x^2}{2}+3\) Reactions: cron1003

cron1003 said: Please help me.. dy + 7x dx = 0 assume dy(0)=3 Click to expand... Separable equation. dy(0)=3 or y(0)=3? \(\displaystyle dy=-7xdx\rightarrow\int dy=-7\int xdx\rightarrow y=\frac{-7x^2}{2}+C_1\) If you mean y(0)=3, then C=3. \(\displaystyle y=\frac{-7x^2}{2}+3\)

C cron1003 Apr 2010 5 0 May 10, 2010 #3 Ops! you are correct. given y(0) = 3. this is correct.. sorry for my mistake.