Hi, I must solve this inequality. How must I proceed?

\(\displaystyle \displaystyle\frac{1}{x^2}<1\)

I don't know how to, couse I cant do this: \(\displaystyle 1<x^2\) so... I know its stupid, but... im a little bit stupid I think.

\(\displaystyle \frac{1}{x^2} < 1

\)

\(\displaystyle \frac{1}{x^2} - 1 < 0\)

\(\displaystyle \frac{1 - x^2}{x^2} < 0\)

critical values are \(\displaystyle x = 1\) , \(\displaystyle x = -1\) , and \(\displaystyle x = 0\)

check the original inequality with a value from each of the four intervals defined by the critical values of x ... if the value makes the original inequality true, then all values of x in that interval make the inequality true.

if false ... all values of x in that interval will not work.