**My Attempt At The Inverse**Let \(\displaystyle g(x)=z\)

\(\displaystyle (x+3)(z)=2x-1\)

\(\displaystyle xz+3z=2x-1\)

\(\displaystyle 1+3z=2x-xz\)

\(\displaystyle 1+3z=x(2-z)\)

\(\displaystyle \frac{1+3z}{2-z}=x\)

\(\displaystyle g^-1(x)=\frac{1+3x}{2-x}\)

Where did I make a mistake?

Thanks!