__Triangle formed by parking meter:__

\(\displaystyle c^2 = a^2 + b^2\)

\(\displaystyle c^2 = 1.3^2 + 1.8^2\)

\(\displaystyle c^2 = \frac{493}{100}\)

\(\displaystyle c = \frac{\sqrt{493}}{10}\)

\(\displaystyle SinA = \frac{O}{H}\)

\(\displaystyle SinA = \frac{1.3}{\frac{\sqrt{493}}{10}}\)

\(\displaystyle Sin^{-1}\frac{1.3}{\frac{\sqrt{493}}{10}} = A\)

\(\displaystyle 35.84^{\circ} = A\)

__Triangle formed by tower (Total triangle):__

\(\displaystyle \frac{a}{SinA} = \frac{b}{SinB}\)

\(\displaystyle \frac{a}{Sin35.84} = \frac{37}{Sin54.16}\)

\(\displaystyle a = Sin35.84(\frac{37}{Sin54.16})\)

\(\displaystyle a = 26.7m\)

*The \(\displaystyle 37m\) value was obtained by adding \(\displaystyle 35.2m\) and \(\displaystyle 1.8m\).

*The \(\displaystyle 54.16^{\circ}\) value was obtained by subtracting \(\displaystyle 90deg\) and \(\displaystyle 35.84deg\) from \(\displaystyle 180deg\).

Therefore, the height of the tower is \(\displaystyle 26.7m\).

Textbook answer: \(\displaystyle 25.4m\).

Where did I make the mistake?