I understand that; that is why I asked the question.

I thought you were asking if it would fit and I said no, that's my final answer lol.

Skeeter makes it harder then need be though (I think...).

For partial fractions,

\(\displaystyle \frac{dy}{1+(y^2)^2 } \)

Let \(\displaystyle P=y^2\) and \(\displaystyle dp=2ydy\)

Noting that \(\displaystyle \sqrt{P}=y\)

We then get,

\(\displaystyle \frac{1}{2 \sqrt{P} } \frac{dp}{1+p^2} = \frac{1}{2} \frac{ dp}{ \sqrt{P} ( 1 + p^2 ) } \)

I believe this will make it easiar to solve.