[SOLVED] Equations of Motion

Sep 2009
148
2
This is just something which has been bothering me and want your expertise on it.

Initial Velocity = 0
Acceleration = 1
Distance = 3

Find the time taken to cover that distance.

So generally I would use the second equation of motion to get an answer

t=2.45s

But why don't I get the same answer when I try to solve it in this way...

\(\displaystyle a=\frac{v}{t}\) and \(\displaystyle v=\frac{d}{t}\)

Thus,

\(\displaystyle a=\frac{d}{t}/t\)

\(\displaystyle a=\frac{d}{t^2}\)

\(\displaystyle 1=\frac{3}{t^2}\)

\(\displaystyle t=1.73s\)

What am I doing wrong? Why don't the answers match?
 

mr fantastic

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This is just something which has been bothering me and want your expertise on it.

Initial Velocity = 0
Acceleration = 1
Distance = 3

Find the time taken to cover that distance.

So generally I would use the second equation of motion to get an answer

t=2.45s

But why don't I get the same answer when I try to solve it in this way...

\(\displaystyle a=\frac{v}{t}\) and \(\displaystyle v=\frac{d}{t}\) Mr F says: These equations give average values.

Thus,

\(\displaystyle a=\frac{d}{t}/t\)

\(\displaystyle a=\frac{d}{t^2}\)

\(\displaystyle 1=\frac{3}{t^2}\)

\(\displaystyle t=1.73s\)

What am I doing wrong? Why don't the answers match?
..
 
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