M muhammetbalikci Nov 2019 3 0 Turkey Nov 19, 2019 #1 Question: Find the slope of the curve's graph at the given point. Then find the equation of tangent and normal line to be graph if exist. I need to your help. y = 2tan(pi.x/4) at x=1

Question: Find the slope of the curve's graph at the given point. Then find the equation of tangent and normal line to be graph if exist. I need to your help. y = 2tan(pi.x/4) at x=1

I Idea Jun 2013 1,149 614 Lebanon Nov 19, 2019 #2 \(\displaystyle f(x)= 2 \tan \left(\frac{\pi x}{4}\right)\) \(\displaystyle f(1)=2\) The equation of the tangent line is of the form \(\displaystyle y-2=m(x-1)\) Reactions: topsquark and muhammetbalikci

\(\displaystyle f(x)= 2 \tan \left(\frac{\pi x}{4}\right)\) \(\displaystyle f(1)=2\) The equation of the tangent line is of the form \(\displaystyle y-2=m(x-1)\)

M muhammetbalikci Nov 2019 3 0 Turkey Nov 19, 2019 #3 Thank you very much. But how can we calculate the derivative of this equation? I couldn't do it.

Cervesa Dec 2014 166 126 USA Nov 19, 2019 #4 chain rule $y' = 2\sec^2\left(\dfrac{\pi x}{4}\right) \cdot \dfrac{\pi}{4}$ Reactions: topsquark and muhammetbalikci