Question: Find the slope of the curve's graph at the given point. Then find the equation of tangent and normal line to be graph if exist. I need to your help.
y = 2tan(pi.x/4) at x=1
y = 2tan(pi.x/4) at x=1
Slope of the curve
- Thread starter muhammetbalikci
- Start date
\(\displaystyle f(x)= 2 \tan \left(\frac{\pi x}{4}\right)\)
\(\displaystyle f(1)=2\)
The equation of the tangent line is of the form
\(\displaystyle y-2=m(x-1)\)
\(\displaystyle f(1)=2\)
The equation of the tangent line is of the form
\(\displaystyle y-2=m(x-1)\)
chain rule
$y' = 2\sec^2\left(\dfrac{\pi x}{4}\right) \cdot \dfrac{\pi}{4}$
$y' = 2\sec^2\left(\dfrac{\pi x}{4}\right) \cdot \dfrac{\pi}{4}$