Ok, so I was playing a dice game with my brother, and he had 3 dice.

On 1 roll he rolled three 1s, and on the next roll three 4s.

I did some quick calculations in my head, and I got the probability of that happening as 1 in 46656... Then realised I may be completely off the mark.

My mental calculations took the root \(\displaystyle 6^3\)x\(\displaystyle 6^3\), or \(\displaystyle 216\)x\(\displaystyle 216\)... I got this because each dice has a 1 in 6 chance of being a certain number (1 through 6), and there were 3 dice each time. I then multiplied the \(\displaystyle 6^3\)s together (obviously also known as \(\displaystyle 6^6\)) to get, after a little thought, 46,656.

This just seems wrong for some reason, please correct me or verify that my reasoning is correct (Rofl)

((Yes, statistics is my weak point, and I'm only 15 anyway (Giggle)))

((Also feel free to be as complicated as you like in any replies, I'm not stupid (Wink)))

On 1 roll he rolled three 1s, and on the next roll three 4s.

I did some quick calculations in my head, and I got the probability of that happening as 1 in 46656... Then realised I may be completely off the mark.

My mental calculations took the root \(\displaystyle 6^3\)x\(\displaystyle 6^3\), or \(\displaystyle 216\)x\(\displaystyle 216\)... I got this because each dice has a 1 in 6 chance of being a certain number (1 through 6), and there were 3 dice each time. I then multiplied the \(\displaystyle 6^3\)s together (obviously also known as \(\displaystyle 6^6\)) to get, after a little thought, 46,656.

This just seems wrong for some reason, please correct me or verify that my reasoning is correct (Rofl)

((Yes, statistics is my weak point, and I'm only 15 anyway (Giggle)))

((Also feel free to be as complicated as you like in any replies, I'm not stupid (Wink)))

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