# Simple basis problem

#### wattkow

I have dosed off in class way too many times and I need help with a few problems from my pre-test:

#2
Let T: M_22 -> M_22 be defined by

$$\displaystyle T \begin{bmatrix} a & b \\ c & d \end{bmatrix} = \begin{bmatrix} a & a-d \\ c+b & d \end{bmatrix}$$

Determine whether
$$\displaystyle \begin{bmatrix} 5 & 3 \\ -1 & 4 \end{bmatrix}$$ is in R(T).
Find a basis for R(T).

A simple hint in the right direction would be greatly appreciated.

#### dwsmith

MHF Hall of Honor
I have dosed off in class way too many times and I need help with a few problems from my pre-test:

#2
Let T: M_22 -> M_22 be defined by

$$\displaystyle T \begin{bmatrix} a & b \\ c & d \end{bmatrix} = \begin{bmatrix} a & a-d \\ c+b & d \end{bmatrix}$$

Determine whether
$$\displaystyle \begin{bmatrix} 5 & 3 \\ -1 & 4 \end{bmatrix}$$ is in R(T).
Find a basis for R(T).

A simple hint in the right direction would be greatly appreciated.

$$\displaystyle \begin{bmatrix} 5 & 3 \\ -1 & 4 \end{bmatrix}$$
$$\displaystyle a=5$$, $$\displaystyle d=4$$, $$\displaystyle a-d=5-4=1$$
$$\displaystyle \begin{bmatrix} 5 & 1 \\ b+c & 4 \end{bmatrix}$$; therefore, $$\displaystyle \begin{bmatrix} 5 & 3 \\ -1 & 4 \end{bmatrix}\notin R(T)$$
$$\displaystyle \begin{bmatrix} a & a-d \\ c+b & d \end{bmatrix}\rightarrow a\begin{bmatrix} 1 & 1 \\ 0 & 0 \end{bmatrix}+b\begin{bmatrix} 0 & 0 \\ 1 & 0 \end{bmatrix}+c\begin{bmatrix} 0 & 0 \\ 1 & 0 \end{bmatrix}+d\begin{bmatrix} 0 & -1 \\ 0 & 1 \end{bmatrix}$$
$$\displaystyle \left(\begin{bmatrix} 1 & 1 \\ 0 & 0 \end{bmatrix}, \begin{bmatrix} 0 & 0 \\ 1 & 0 \end{bmatrix}, \begin{bmatrix} 0 & 0 \\ 1 & 0 \end{bmatrix},\begin{bmatrix} 0 & -1 \\ 0 & 1 \end{bmatrix}\right)$$