It's a sketch of an upwards curving parabola (f) and a straight line (g). The parabola has a vertex B, it cuts the x-axis at (0,2) and the other x-intercept is only given as D. The y-intercept therefore is (0,-6), right?

g cuts the parabola at point E on the y-axis and at A. the equation for g is given as g(x) = y=x+c

Any tips on how to find a in y=ax^2-x-6?

Thanks in advance