sampling distibution

May 2010
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can anyone help me with understanding how to do this problem.

based on past experience a bank believes 12% of people who receive loans do not pay on time. The bank recently approved 400 new loans.

what is the mean and standard deviation of the proportion of clients who may not pay on time?

what is the probability that over 14% of these clients will not make timely payments?
 

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can anyone help me with understanding how to do this problem.

based on past experience a bank believes 12% of people who receive loans do not pay on time. The bank recently approved 400 new loans.

what is the mean and standard deviation of the proportion of clients who may not pay on time?

what is the probability that over 14% of these clients will not make timely payments?
X ~ Binomial(n = 400, p = 0.12).

For the second part, you're probably expected to use the the normal approximation to the Binomial distribution. Note: 14% of 400 = 56.