Hi, I am having trouble with this problem. My Geometry text book explains how to do this, but not very well, and I have come to a problem on a practice test that is nothing like what's in the book. I would really appriciate some help with this please!

*Figure is a right triangle

Question: Given the Figure below (right triangle), find ,
a if sin B = 0.42, cos B = 0.91, tan B = 0.47 and c =60

Hi, I am having trouble with this problem. My Geometry text book explains how to do this, but not very well, and I have come to a problem on a practice test that is nothing like what's in the book. I would really appreciate some help with this please!

*Figure is a right triangle

Question: Given the Figure below (right triangle), find ,
a if sin B = 0.42, cos B = 0.91, tan B = 0.47 and c =60

Since you know the value of sin B and c, you could simply use the equation
sin B=b/c
to calculate b and then plug this into Pythagorean theorem
a^2+b^2=c^2
to get a.

But even simpler: If you know that in right triangle sin A=cos B, then you have
cos B=sin A=a/c
from which you can easily get a.

(I guess that A is the angle opposite to the side a and B is the angle opposite to the side b - this is probably shown in the figure you did not show us. Am I right?)

Hi, I am having trouble with this problem. My Geometry text book explains how to do this, but not very well, and I have come to a problem on a practice test that is nothing like what's in the book. I would really appriciate some help with this please!

*Figure is a right triangle

Question: Given the Figure below (right triangle), find ,
a if sin B = 0.42, cos B = 0.91, tan B = 0.47 and c =60