Richter scale

Mar 2010
14
0
Hi!

I would really appraciate som help with this following problem. My apologies if this is en the wrong thread but im a swede and my english terms in mathematics isn't all that great :p

Now for the task:

\(\displaystyle
M = 2/3(log10E-4.4)
\)
M is the magnitude and E the energy which is released during and earthquake.

> Solve this equation with respect to E..

> A powerful earthquake has the magnitude 8.0 on the Richterscale. How much energy i released in such an earthquake?

I've started with this one:
\(\displaystyle 8.0 = 2/3(log10E-4.4) \)
\(\displaystyle 12 = log10E-4.4 \)
\(\displaystyle 16.4 = log10E \)

and now im stuck :)


Any help regarding these two tasks would be great :)

Best Regards
 
May 2010
78
6
Tanzania
\(\displaystyle Log10E = 16.4
Log10E = Log 16.4\) Take log of the other side of the equation

E = Log16.4/Log10[/tex]

E = 1.2148

Hope it helps.
 
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Mar 2010
14
0
thank you for the quick reply!

I thought this was the next step but i got confused regarding the result.

Isn't it to small? 1.21... Joule sounds very little when it supposed to be a big earthquake?

thx again
 

HallsofIvy

MHF Helper
Apr 2005
20,249
7,909
BobBall was thinking that your "log10E" was "logarithm of 10 times E" when I think you meant "\(\displaystyle log_{10}E\), the "logarithm, base 10, of E".

So from \(\displaystyle log_{10}E= 16.4\) use the inverse logarithm (\(\displaystyle 10^x\) on a calculator to get 25118864315095801, approximately.
 
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