# Richter scale

#### DenOnde

Hi!

I would really appraciate som help with this following problem. My apologies if this is en the wrong thread but im a swede and my english terms in mathematics isn't all that great $$\displaystyle M = 2/3(log10E-4.4)$$
M is the magnitude and E the energy which is released during and earthquake.

> Solve this equation with respect to E..

> A powerful earthquake has the magnitude 8.0 on the Richterscale. How much energy i released in such an earthquake?

I've started with this one:
$$\displaystyle 8.0 = 2/3(log10E-4.4)$$
$$\displaystyle 12 = log10E-4.4$$
$$\displaystyle 16.4 = log10E$$

and now im stuck Any help regarding these two tasks would be great Best Regards

#### BobBali

$$\displaystyle Log10E = 16.4 Log10E = Log 16.4$$ Take log of the other side of the equation

E = Log16.4/Log10[/tex]

E = 1.2148

Hope it helps.

• DenOnde

#### DenOnde

thank you for the quick reply!

I thought this was the next step but i got confused regarding the result.

Isn't it to small? 1.21... Joule sounds very little when it supposed to be a big earthquake?

thx again

#### HallsofIvy

MHF Helper
BobBall was thinking that your "log10E" was "logarithm of 10 times E" when I think you meant "$$\displaystyle log_{10}E$$, the "logarithm, base 10, of E".

So from $$\displaystyle log_{10}E= 16.4$$ use the inverse logarithm ($$\displaystyle 10^x$$ on a calculator to get 25118864315095801, approximately.

• DenOnde
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