Rationalizing denominator

Oct 2009
303
33
I just need to understand how rationalized \(\displaystyle \frac{2}{\sqrt{2\pi}}\) to get \(\displaystyle \sqrt{\frac{2}{\pi}}\)

When I rationalized, I just multiplied by \(\displaystyle \frac{\sqrt{2\pi}}{\sqrt{2\pi}}\) and got \(\displaystyle \frac{\sqrt{2\pi}}{\pi}\)
 

chiro

MHF Helper
Sep 2012
6,608
1,263
Australia
Hey downthesun01.

Hint: 2 = SQRT(2)*SQRT(2) and SQRT(2*pi) = SQRT(2)*SQRT(pi).
 
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Prove It

MHF Helper
Aug 2008
12,897
5,001
The result does not have a rational denominator. It is just a simplification.