D downthesun01 Oct 2009 303 33 Jul 28, 2013 #1 I just need to understand how rationalized \(\displaystyle \frac{2}{\sqrt{2\pi}}\) to get \(\displaystyle \sqrt{\frac{2}{\pi}}\) When I rationalized, I just multiplied by \(\displaystyle \frac{\sqrt{2\pi}}{\sqrt{2\pi}}\) and got \(\displaystyle \frac{\sqrt{2\pi}}{\pi}\)

I just need to understand how rationalized \(\displaystyle \frac{2}{\sqrt{2\pi}}\) to get \(\displaystyle \sqrt{\frac{2}{\pi}}\) When I rationalized, I just multiplied by \(\displaystyle \frac{\sqrt{2\pi}}{\sqrt{2\pi}}\) and got \(\displaystyle \frac{\sqrt{2\pi}}{\pi}\)

C chiro MHF Helper Sep 2012 6,608 1,263 Australia Jul 28, 2013 #2 Hey downthesun01. Hint: 2 = SQRT(2)*SQRT(2) and SQRT(2*pi) = SQRT(2)*SQRT(pi). Reactions: 1 person

Prove It MHF Helper Aug 2008 12,897 5,001 Jul 29, 2013 #3 The result does not have a rational denominator. It is just a simplification.