# Ration of sin of angles

#### jacks

In a $$\displaystyle \Triangle ABC\;,$$ If $$\displaystyle \tan A:\tan B;\ \tan C = 1: 2:3\;,$$ Then $$\displaystyle \sin A: \sin B: \sin C,$$ is

#### chiro

MHF Helper
He jacks.

Hint - Tan(x) = sin(x)/cos(x) along with the understanding of a completely positive relationship (which will limit quadrants).

#### yeongil

In a $$\displaystyle \Triangle ABC\;,$$ If $$\displaystyle \tan A:\tan B;\ \tan C = 1: 2:3\;,$$ Then $$\displaystyle \sin A: \sin B: \sin C,$$ is
To show a triangle in LaTeX, the code is \bigtriangleup, not \triangle:
$$\displaystyle \bigtriangleup ABC$$

Let tan A = k, tan B = 2k, and tan C = 3k. Since we have a triangle ABC, use the identity
$$\displaystyle \tan A + \tan B + \tan C = \tan A \tan B \tan C$$,
make substitutions, and solve for k. (There will actually be 3 solutions for k, but only one will be valid.) You'll then find that angle A is a special angle. Angles B and C are not "nice" angles (not whole numbers in degrees), however.

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