sqrt{sqrt{6 + 4sqrt{2}} = sqrt{2 + sqrt{2}}.

I let d = sqrt{2 + sqrt{2}}.

I was able to complete the prove by hand but NOT without using Wolfram to simplify a portion of the problem.

I factored the radicand of sqrt{6 + 4sqrt{2}} to become sqrt{2(3 + 2sqrt{2})}.

According to Wolfram:

sqrt{6 + 4sqrt{2}} = sqrt{2(3 + 2sqrt{2})} = 2 + sqrt{2}.

QUESTION:

How do I manipulate the radical sqrt{2(3 + 2sqrt{2})} to become 2 + sqrt{2}?