quadratctic fomula's

May 2010
43
0
I entered a new era of erm...unhappiness when it comes to this...Could someone help with these...

Using the quadratic formula to solve x2 – 4 = 0 and -4x2 + 4x + 80 = 0

This keeps getting harder lol I know how to do the simple ones but when they are switched up like that it gets hard...
 
Feb 2010
1,036
386
Dirty South
I entered a new era of erm...unhappiness when it comes to this...Could someone help with these...

Using the quadratic formula to solve x2 – 4 = 0 and -4x2 + 4x + 80 = 0

This keeps getting harder lol I know how to do the simple ones but when they are switched up like that it gets hard...
\(\displaystyle x^2 - 4 = 0\)

\(\displaystyle x^2 - (2)^2 = 0\)

since \(\displaystyle a^2 - b^2 = (a+b)(a-b)\)

you can write \(\displaystyle (x+2)(x-2) = 0\) and find x.

for \(\displaystyle -4x^2+4x+80=0\) use the quadratic equation formula.

For a quadratic equation \(\displaystyle ax^2+bx+c=0\), you can find x as:

\(\displaystyle x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\)

use a, b, and c from your equation to find x.
 
May 2010
43
0
\(\displaystyle x^2 - 4 = 0\)

\(\displaystyle x^2 - (2)^2 = 0\)

since \(\displaystyle a^2 - b^2 = (a+b)(a-b)\)

you can write \(\displaystyle (x+2)(x-2) = 0\) and find x.

for \(\displaystyle -4x^2+4x+80=0\) use the quadratic equation formula.

For a quadratic equation \(\displaystyle ax^2+bx+c=0\), you can find x as:

\(\displaystyle x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\)

use a, b, and c from your equation to find x.
It seems (x = -5) (x = 10) could be appropiate right?
 
Feb 2010
1,036
386
Dirty South
It seems (x = -5) (x = 10) could be appropiate right?
Looks like you have not seen that formula before.. What method does your book or your class instructor follow to solve these type of questions?
 
May 2010
43
0
Looks like you have not seen that formula before.. What method does your book or your class instructor follow to solve these type of questions?
Actually it's online, and the lesson has that formula but the answers are a bit different, the one you solved for me was

x = -2 or x = 2 as an anser for my class, I could tell the difference between your anser in mine, though they looked different I think it's the same either way.
 
Feb 2010
1,036
386
Dirty South
Actually it's online, and the lesson has that formula but the answers are a bit different, the one you solved for me was

x = -2 or x = 2 as an anser for my class, I could tell the difference between your anser in mine, though they looked different I think it's the same either way.
(x+2)(x-2)=0 means that x = 2 or x = -2 is your answer..

I was talking about the second problem.. Are you supposed to use the formula I gave earlier on, or are you supposed to do it by completing the square?
 
May 2010
43
0
(x+2)(x-2)=0 means that x = 2 or x = -2 is your answer..

I was talking about the second problem.. Are you supposed to use the formula I gave earlier on, or are you supposed to do it by completing the square?
Oh, it says use the quadratic formula but I got the anwser
x = -5 or x = 10
 
Feb 2010
1,036
386
Dirty South
Oh, it says use the quadratic formula but I got the anwser
x = -5 or x = 10
If your question is \(\displaystyle -4x^2+4x+80=0\), then the answer you have gotten is wrong...

plug in a= -4 , b = 4 and c =80 in the formula given in Post#2 and find x..
 
May 2010
43
0
If your question is \(\displaystyle -4x^2+4x+80=0\), then the answer you have gotten is wrong...

plug in a= -4 , b = 4 and c =80 in the formula given in Post#2 and find x..
x = 5 or x = -4?