# proportioned angles

#### msbiljanica

Required accessories - pencil, compass, unmarked straightedge Odd proportion angles (there is a proportion of the steam angles) of the element 3 (which may be 5,7,9, ...) and the base angle $$\displaystyle 45 ^ o$$ (which can be any angle which is obtainable by means of compass and straightedge)

The angle CAB $$\displaystyle 45 ^ o$$ can be obtained with a compass and unmarked ruler, he added angles (each have $$\displaystyle 45 ^ o$$) DAC and EAD, obtained angle EAB $$\displaystyle 135 ^ o$$is the starting angle

Merge points E (D, C, B) and get a longer ED (DC, CB)

Along the DC from the point C draw is normal that intersects the segment AB, the intersection is a point G

Divider AG and from point G draw a circular arc to a longer EA and H get the point, and the arc GH, join the dots G and H and get along GH

Longer GH (ED, DC, CB) are equal, the arc EB's first circular arc can be made smaller or larger with a constant radius AB, arc GH is the second circular arc can be made smaller or larger with a constant radius AG

INCREASING THE ANGLE
the starting angle EAB add angle FAE $$\displaystyle 15 ^ o$$ get the angle FAB $$\displaystyle 150 ^ o$$ - continued in the next post

#### msbiljanica

- previous post was in error - Required accessories - pencil, compass, unmarked straightedge

basic angle - can be any angle that can be construction using compass and unmarked straightedge, angle CAB $$\displaystyle 45 ^ o$$

starting angle - sum of 2, 3, 4, 5, ... basic angles , EAB $$\displaystyle 135 ^ o$$
sum angles CAB $$\displaystyle 45 ^ o$$ DAC $$\displaystyle 45 ^ o$$ EAD $$\displaystyle 45 ^ o$$

difference angle - the angle which increases or decreases the starting angle. difference starting angle and the angle of whom do not know the measure , this angle is known to see a procedure HAB $$\displaystyle 30 ^ o$$

straightedge AB is divided into three parts AF , how we have a basis in the angles starting angle

divider AF from point A the circular arc FG

section straightedge AH the circular arc FG , point I

straightedges FG , ED
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will continue - if there are errors

#### msbiljanica

basic angle CAB $$\displaystyle 45^o$$

starting angle EAB $$\displaystyle 135^o$$ consists of the sum of the angles CAB $$\displaystyle 45^o$$ DAC $$\displaystyle 45^o$$EAD $$\displaystyle 45^o$$

DC straightedge the normal to the point D , gets the point F

AF divider from point A, we get the point G

divider AB from point F, divider AB from point G, we get the point H

HG divider from point H, creates a circular arc FG

difference angle IAB $$\displaystyle 30^o$$

section IA and longer circular arc FG is a point J #### HallsofIvy

MHF Helper
What was your purpose in posting this? Do you have a question? You are doing a construction but you do not say what you are trying to construct.

#### HallsofIvy

MHF Helper
So you are just going to keep chattering without telling us what you are talking about?

#### msbiljanica

So you are just going to keep chattering without telling us what you are talking about?
I found the proportion of angles to us to make sure that the process has errors

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