S sab456 Oct 2012 2 0 USA Oct 31, 2012 #1 Hello, I have been trying to find out if 'Aristarchus' Theorem' can be solved geometrically. It states that if 0 < α < β < pi/2 then Sin(α)/α > Sin(β)/β Can you folks think of a possible way of proving this geometrically ? Many thanks

Hello, I have been trying to find out if 'Aristarchus' Theorem' can be solved geometrically. It states that if 0 < α < β < pi/2 then Sin(α)/α > Sin(β)/β Can you folks think of a possible way of proving this geometrically ? Many thanks

S Salahuddin559 Oct 2012 61 3 India Oct 31, 2012 #2 How about a unit circle? The length on perimeter is equals to angle theta, and the side approximating it in the right triangle will be sin(theta). Salahuddin Maths online

How about a unit circle? The length on perimeter is equals to angle theta, and the side approximating it in the right triangle will be sin(theta). Salahuddin Maths online

E elisaevedent Nov 2012 10 0 nagercoil Nov 1, 2012 #3 Was Aristarchus of Samos wrong because he failed to meet the burden of proof? san diego dentist