D DenOnde Mar 2010 14 0 May 12, 2010 #1 Need a little help here... what is the primitive funktion of: \(\displaystyle (0,5x^2)^2\) and what is the way of finding it? Best regards

Need a little help here... what is the primitive funktion of: \(\displaystyle (0,5x^2)^2\) and what is the way of finding it? Best regards

S shenanigans87 Apr 2010 57 19 May 12, 2010 #2 DenOnde said: Need a little help here... what is the primitive funktion of: \(\displaystyle (0,5x^2)^2\) and what is the way of finding it? Best regards Click to expand... I don't understand the equation you wrote down... The primitive function is the antiderivative. So if the function were \(\displaystyle (5x^2)^2=25x^4\) then the primitive function is \(\displaystyle 5x^5\) because when you take its derivative, you get \(\displaystyle 25x^4\) Reactions: DenOnde

DenOnde said: Need a little help here... what is the primitive funktion of: \(\displaystyle (0,5x^2)^2\) and what is the way of finding it? Best regards Click to expand... I don't understand the equation you wrote down... The primitive function is the antiderivative. So if the function were \(\displaystyle (5x^2)^2=25x^4\) then the primitive function is \(\displaystyle 5x^5\) because when you take its derivative, you get \(\displaystyle 25x^4\)

D DenOnde Mar 2010 14 0 May 12, 2010 #3 aha, it was the outer square of the equation that had me dazzled. the equation was: \(\displaystyle ((x^2)/2)^2\) so that correct answer should be: \(\displaystyle 0,05x^5\)? Thanx for the quick reply by the way

aha, it was the outer square of the equation that had me dazzled. the equation was: \(\displaystyle ((x^2)/2)^2\) so that correct answer should be: \(\displaystyle 0,05x^5\)? Thanx for the quick reply by the way

S shenanigans87 Apr 2010 57 19 May 12, 2010 #4 DenOnde said: aha, it was the outer square of the equation that had me dazzled. the equation was: \(\displaystyle ((x^2)/2)^2\) so that correct answer should be: \(\displaystyle 0,05x^5\)? Thanx for the quick reply by the way Click to expand... The answer would be \(\displaystyle \frac{x^5}{20}+C\) the C is necessary because its some unknown constant. Reactions: DenOnde

DenOnde said: aha, it was the outer square of the equation that had me dazzled. the equation was: \(\displaystyle ((x^2)/2)^2\) so that correct answer should be: \(\displaystyle 0,05x^5\)? Thanx for the quick reply by the way Click to expand... The answer would be \(\displaystyle \frac{x^5}{20}+C\) the C is necessary because its some unknown constant.

D DenOnde Mar 2010 14 0 May 12, 2010 #5 Not in this case I was looking for the primitiv form in a integral so the C is not necessery this time Thank you for the help! Really appreciate it

Not in this case I was looking for the primitiv form in a integral so the C is not necessery this time Thank you for the help! Really appreciate it