So \(\displaystyle \int{\frac{1}{3 + x}\,dx} = \ln{(3 + x)}\).

So if you have a power series for \(\displaystyle \frac{1}{3 + x}\), integrate it, then you will have a power series for \(\displaystyle \ln{(3 + x)}\).

So \(\displaystyle \int{\frac{1}{3 + x}\,dx} = \ln{(3 + x)}\).

So if you have a power series for \(\displaystyle \frac{1}{3 + x}\), integrate it, then you will have a power series for \(\displaystyle \ln{(3 + x)}\).