S saha.subham Jul 2009 68 0 May 19, 2010 #1 for what value of h is the polynomial f(x) = 2x^3 - hx^2 + 5x + 9 exactly divisible by x + 2 ?

slovakiamaths Apr 2010 41 15 India May 19, 2010 #2 \(\displaystyle put x+2=0\) x=-2 now \(\displaystyle 2x^3-hx^2+5x+9=0\) \(\displaystyle 2(-2)^3-h(-2)^2+5(-2)+9=0\) \(\displaystyle h=\frac{-17}{4}\) Reactions: saha.subham

\(\displaystyle put x+2=0\) x=-2 now \(\displaystyle 2x^3-hx^2+5x+9=0\) \(\displaystyle 2(-2)^3-h(-2)^2+5(-2)+9=0\) \(\displaystyle h=\frac{-17}{4}\)