Q: Obtain the area inside \(\displaystyle r=1+cos\theta\) and outside \(\displaystyle r=3cos\theta\)

My first attempt was \(\displaystyle A=2\int_{\frac{\pi}{3}}^{\pi}\int_{3cos\theta}^{1+cos\theta}rdrd\theta\) which I quickly realized has incorrect angles, since \(\displaystyle r=3cos\theta\) loops around twice as fast as the other graph. Thank you!

My first attempt was \(\displaystyle A=2\int_{\frac{\pi}{3}}^{\pi}\int_{3cos\theta}^{1+cos\theta}rdrd\theta\) which I quickly realized has incorrect angles, since \(\displaystyle r=3cos\theta\) loops around twice as fast as the other graph. Thank you!

**EDIT - I have just figured it out on my own! Sorry about that**
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