From the data you calculated the sample mean (\(\displaystyle \bar{x}\)) to be 56.83.

So a 95% confidence inteveral for the population mean (\(\displaystyle \mu \)) is

\(\displaystyle \Big[56.83 - 1.96* \frac{2}{\sqrt{10}}, \ 56.83 + 1.96*\frac{2}{\sqrt{10}}\Big] \)

[55.59, 58.07]

Now either this interval contains \(\displaystyle \mu \) or it doesn't. But if you constructed many such intervals by taking different samples of the same size, 95% of them would contain \(\displaystyle \mu \).