plz can any one help me to plot this equation

Apr 2015
9
0
algeria
i want to plot θ against β

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°
(Speechless)
 

topsquark

Forum Staff
Jan 2006
11,602
3,458
Wellsville, NY
In order to plot this in a "traditional" sense you would have to solve for \(\displaystyle \beta\) as a function of \(\displaystyle \theta\). This is not going to be easy for this case, but it is possible. The better way would be to plot this as a "relation" rather than as a function. There are a number of online resources that you can find that will do this for you. Wolfram|Alpha is a good site but I don't remember off the cuff how to tell it to graph this.

-Dan
 
Dec 2012
1,145
502
Athens, OH, USA
Here's your graph; $\theta$ and $\beta$ are in radians. The red "curve" is your graph. You can see that $\beta$ is not a function of $\theta$ and $\theta$ is not a function of $\beta$. The given relation's graph for arbitrary theta and beta is shown outside the red square.

 
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Apr 2015
9
0
algeria
thank you johng, i have seen this result , but in ohter side some give this plot. i m not understund how obtain this graph

maths.png
 
Apr 2015
9
0
algeria
thank you topsquark, i want to obtain this graph

maths.png
 
Apr 2015
9
0
algeria
i have an other condition can help !!!

cos(θ-β)-2sin(2(θ-β))-cos(2θ)≥0
 

chiro

MHF Helper
Sep 2012
6,608
1,263
Australia
Try solving for the derivative at a particular point and then step through it based on that.

You can solve plotting of relations that aren't functions in this manner.