Please help me to solve this poker formula (Implied Odds)

Jun 2019
4
0
BKK
Hi guys! My math skills are very poor, so i decided to post a thread and ask you about help. I can't solve it by myself. I am rookie poker player and my question is about Implied Odds. At the top will be description of the situation ( i took it from one poker site ) and after i will post a formula.

Implied Odds:


Imagine you’re playing a $1/$2 cash game and you have K♥ Q♥ on the turn in position. The board is A♥ 6♦ 2♠ 9♥ — giving you the nut flush draw — and your opponent bets $15 into a $20 pot.
A quick pot odds calculation ($15 to call / ($15 bet + $20 pot + $15 call) = 0.3) shows that you need more than 30% equity to profitably call. Since you only have a ~20% chance to hit the flush with one card to come, you would have to fold this hand if no future action is taken into consideration.


This is where implied odds come in. Here is the formula for figuring out how much money you’d need to win on the river to justify a call on the turn:



You may notice that this is very similar to the formula for pot odds. The only differences are the added “X” in the denominator and your hand’s equity on the right-hand side of the equation. Now, let’s solve for ‘X’.




This means, when you hit the flush on the river with K♥ Q♥, you will need to win more than $25 to make the turn call profitable. Since the pot is already $50, you would only have to extract a half pot bet on the river on average. That result seems quite feasible, especially with the potential to win a huge pot in flush-over-flush situations. So, you should call on the turn in this hand.

My Question:

I didn't get how 25$ came out (X). Could you please explain to me like you would explain to your kid?
 

Walagaster

MHF Helper
Apr 2018
230
146
Tempe, AZ
Are you just asking about the last step? You have $.2 x = 5$ or $\frac 2 {10} x = 5$. Multiply both sides by $10$ getting $2x = 50$ then divide both sides by $2$ to get $x=25$.
 
Jun 2019
4
0
BKK
Yeah! exactly what i wanted. Could you please explain last step in details. Although you already did it, i feel dumb because it's hard for me to grasp it. I will be eternally grateful.

.2x=5 or 2/10x=5.( 10 we get before be multipy 0.2x50 ) So X is 5$

"Multiply both sides by 10 getting 2x=50 then divide both sides by 2 to get x=25"

This part i don't understand.
 
Jun 2019
4
0
BKK
Walagaster I don't understand second part. Could you explain please. Im feel dumb, i am completely noob at math.

"You have.2x=5 or 2/10 x"

So this .2x= our hand equity? For example if all the data was the same instead of EQ, lets say eQ is 0.3 now, so it's gonna be .03x= 5 or 15/3=5 am i correct?

And i dont understand second part with miltiplaying both sides by 10 in original example.

 
Jun 2019
4
0
BKK
Are you just asking about the last step? You have $.2 x = 5$ or $\frac 2 {10} x = 5$. Multiply both sides by $10$ getting $2x = 50$ then divide both sides by $2$ to get $x=25$.
I don't understand second part (miltiplaying both sides by 10). Could you explain please. Im feel dumb, i am completely noob at math.

"You have.2x=5 or 2/10 x"

So this .2x= our hand equity? For example if all the data was the same instead of EQ, lets say eQ is 0.3 now, so it's gonna be .03x= 5 or 15/3=5 am i correct?
 

Walagaster

MHF Helper
Apr 2018
230
146
Tempe, AZ
You have $\frac 2 {10} x = 5$ and you are trying to solve it for $ x$. I suggested to you to multiply both sides by $10$. Are you saying you not know how to multiply $\frac 2 {10}$ by $10$? And on the other side multiply $5$ by $10$? And after you have done that you don't know how to divide both sides by $2$? If that's really what is puzzling you, I"m afraid you need more help than I can give you. You might want to dig out a beginning algebra book.