Find the line of intersection for the two planes:

1: 0t 3 − 2 − 1 = 0

2: 2 + 4 + − 5 = 0

let = (a scalar)

0+3 − 2 − 1 = 0…(1)

2 + 4 + − 5 = 0.….(2)

use substitution to find the value of y from equation (1):

0+3 − 2 − 1 = 0…………..(1)

3= 2+ 1

=2+13………(3)

eliminate the variable y from the equations:

First Multiply equation (1) by 4, and multiply equation (2) by -3:

0+12 −8 − 4 = 0

−6−12−3+15 = 0

Use the elimination method:

0+12 −8 − 4 = 0

−6−12−3+15 = 0

−6−11+11=0

−6−11=−11…(4)

−11=−11+6

=−6/11+1

y:

Substitute the value of z into equation (3):

=2+13

=2(−6/11+1)

=(−4−11)/11

I am very confused by the decimal values...Does my working make sense? I would appreciate any help