Perpendicular linear equations.

May 2010
37
0
How would you solve...
In the xy-plane, the graph of which of the following linear equations is perpendicular to the graph of the linear equation 3x-4y=0?
 

Plato

MHF Helper
Aug 2006
22,460
8,632
How would you solve...
In the xy-plane, the graph of which of the following linear equations is perpendicular to the graph of the linear equation 3x-4y=0?
What lines?
Any line perpendicular to the given line looks like:
\(\displaystyle 4x+3y=K\).
 
May 2010
37
0
Oh. Sorry. (Speechless)

A) y= -4/3x + 12
B) y= -3/4x + 12
C) y= 3/4x + 12
D) y= 4/3x + 12

I don't know how to find a perpendicular line and when I tried it on a graphing calculator I got it wrong. They say the answer is A but I didn't know how they got that.
 

Plato

MHF Helper
Aug 2006
22,460
8,632
Oh. Sorry. (Speechless)

A) y= -4/3x + 12
B) y= -3/4x + 12
C) y= 3/4x + 12
D) y= 4/3x + 12

I don't know how to find a perpendicular line and when I tried it on a graphing calculator I got it wrong. They say the answer is A but I didn't know how they got that.
Put the answer I gave into the slope-intercept form. You will see it.
 
May 2010
37
0
Alrighty. I see it now.
Thanks so much. (Nod)