S sa-ri-ga-ma Jun 2009 806 275 Jun 1, 2010 #2 {3x}/{(3-2x)^{2} = {A}/(3-2x) + {B}/{(3-2x)^{2} 3x = A(3-2x) + B Compare the3 coefficients to find A and B. Reactions: Cthul

{3x}/{(3-2x)^{2} = {A}/(3-2x) + {B}/{(3-2x)^{2} 3x = A(3-2x) + B Compare the3 coefficients to find A and B.

Cthul Mar 2010 71 2 Jun 1, 2010 #3 sa-ri-ga-ma said: \(\displaystyle \frac{3x}{(3-2x)^2}\) = \(\displaystyle \frac{A}{3-2x}+\frac{B}{(3-2x)^2}\) 3x = A(3-2x) + B Compare the3 coefficients to find A and B. Click to expand... Thanks, got it.

sa-ri-ga-ma said: \(\displaystyle \frac{3x}{(3-2x)^2}\) = \(\displaystyle \frac{A}{3-2x}+\frac{B}{(3-2x)^2}\) 3x = A(3-2x) + B Compare the3 coefficients to find A and B. Click to expand... Thanks, got it.