One more simple problem

Sep 2009
11
0
Anyway I've seem to come across another problem..

Angle A = 25 degrees
Side Z = 85 units
Side Z is opposite of Angle A
Side Y is the hypotenuse
Side X is the adjacent

\(\displaystyle \sin(25)=\frac {85}{y}\)

I tried solving this using this method.. whatever it is..

Step 1. \(\displaystyle \frac {\sin(25)}{1} = \frac {85}{y}\)

Step 2. \(\displaystyle y\sin(25)=85\)

Step 3. \(\displaystyle y=\frac {85}{\sin(25)}\)

Step 4. \(\displaystyle y=-642.228\)

Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1.

Thanks again for all who contribute.
 

e^(i*pi)

MHF Hall of Honor
Feb 2009
3,053
1,333
West Midlands, England
Anyway I've seem to come across another problem..

Angle A = 25 degrees
Side Z = 85 units
Side Z is opposite of Angle A
Side Y is the hypotenuse
Side X is the adjacent

\(\displaystyle \sin(25)=\frac {85}{y}\)

I tried solving this using this method.. whatever it is..

Step 1. \(\displaystyle \frac {\sin(25)}{1} = \frac {85}{y}\)

Step 2. \(\displaystyle y\sin(25)=85\)

Step 3. \(\displaystyle y=\frac {85}{\sin(25)}\)

Step 4. \(\displaystyle y=-642.228\)

Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1.

Thanks again for all who contribute.
Why can't it be less than 1? If anything we know it must be bigger than 85 because the hypotenuse is the longest side.

Either way your working is fine, I've not checked the arithmetic since I've misplaced my calculator
 
Dec 2009
3,120
1,342
Anyway I've seem to come across another problem..

Angle A = 25 degrees
Side Z = 85 units
Side Z is opposite of Angle A
Side Y is the hypotenuse
Side X is the adjacent

\(\displaystyle \sin(25)=\frac {85}{y}\)

I tried solving this using this method.. whatever it is..

Step 1. \(\displaystyle \frac {\sin(25)}{1} = \frac {85}{y}\)

Step 2. \(\displaystyle y\sin(25)=85\)

Step 3. \(\displaystyle y=\frac {85}{\sin(25)}\)

Step 4. \(\displaystyle y=-642.228\) your calculator was in radian mode

Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1. cannot be <0

Thanks again for all who contribute.
There are \(\displaystyle 2{\pi}\) radians in a circle.
As the angle is 25 degrees, your calculator needs to be in degree mode.
 
Last edited:
Sep 2009
11
0
Thank you both.

Didn't realize that my calculator was in radian mode, silly me :p