Number of ways.

Dec 2009
61
0
How many five digit natural numbers, with different digits can be formed from the digits 1 to 9 if each number is to contain three odd digits and two even digits?
 
Dec 2009
61
0
I honestly have no idea how to do this q..
Can someone give me an idea of how to start it?
 
Jun 2008
292
87
even numbers: 2,4,6,8
odd numbers : 1,3,5,7,9
we have to form a number 5 digit number with 3 odd digits and two even digits
now number of ways in which 3 odd numbers can be taken=5C3
number of ways in which 2 even numbers can be taken=4C2
now number of ways of forming the number=5C3*4C2*5!
because each combination obtained can be written in 5! ways