P Psykik Aug 2019 1 0 Australia Aug 1, 2019 #1 [FONT="]I have a Lissajous curve with the equations x=cos(2*t) and y=sin(t) for 0<t<2(pi). I need to find thae cartesian equation for this and I am really stuck. Any help is greatly appreciated[/FONT]

[FONT="]I have a Lissajous curve with the equations x=cos(2*t) and y=sin(t) for 0<t<2(pi). I need to find thae cartesian equation for this and I am really stuck. Any help is greatly appreciated[/FONT]

I Idea Jun 2013 1,112 590 Lebanon Aug 1, 2019 #2 trig identity $$\cos (2t)=1-2 \sin ^2t$$ Reactions: 1 person